精華區beta NTU-Exam 關於我們 聯絡資訊
課程名稱︰普通化學乙上 課程性質︰必帶 課程教師︰林英智教授 開課學院:工學院 開課系所︰材料系 考試日期(年月日)︰2009.12.01 考試時限(分鐘):115(1020~1215) 是否需發放獎勵金:yes (如未明確表示,則不予發放) 試題 : 1. Titrating 15.00 mL of a saturated calcium iodate solution requires 14.46 mL of Na2S2O3 according to the equation IO3- +6S2O3 2- --> I- +3S4O6 2- +3H2O\ Calculate Ksp for Ca(IO3)2 2. Derive the equation P1V1^r=P2V2^r for a reversible, adiabatic change from V1 to V2 of an ideal gas, and determine the value of r=? 3. Calculate (deltaH0) fpr tje oxidation of SO2 to SO3 at 798K and constant pressure. SO2(g)+1/2O2(g)-->SO3(g) 4. Consider the reaction H2(g)+F2(g)-->2HF(g) a)Using the thermochemical data. calculate (deltaG0) at 298K b)Calculate (deltaG) at 298K if the reaction mixture consists of 8.0atm of H2, 4.5 atm of F2, and 0.36atm of HF 5. Consider the following equilibrium: N2O4(g)-->2NO2(g) Using the thermochemical data. You may assume that (deltaH0) and (deltaS0) do not vary with temperature. a)At what temperature will an equilibrium mixture contain equal amounts of the two gases. b)At what temperature will an equilibrium mixture of 1.00 atm total pressure contain twice as much NO2 as N2O4? c)At what temperature will an equilibrium mixture of 10.0 atm total pressure contain as much NO2 as N2O4? 6. Use the thermochemical tables to evaluate (deltaG0) and K for the condensation of one mole of mercury at 298K. What is the vapor pressure of mercury at this temperature? 7. 1.0018g of benzoic acid, C6H5COH , is burned in a bomb calorimeter of heat capacity 9.018kJ/K. The initial temperature is 298.000K and the final temperature is 300.934K. Use equation (deltaU0)=-Ccal(t2-t1) to estimate (deltaU0) for the reaction and hence estimate (deltaU0) and (delta H0) per mole of benzoic acid. 8. Consider 1.00 mol of an ideal gas at 298K. a)Calculate q,w,(deltaE),(delta S),(delta H), and (delta G) for the expansion of this gas isothermally and irreversibly from 2.45x10^-2 atm to 2.45x10^-3 atm in one step. b)Calculate q,w,(delta E), (delta S), (delta H), and (delta G) for the same change of pressure as in part a but performed isothermally and reversibly. c)Calculate q,w, (delta E), (delta S), (delta H), and (delta G) for the one-step isothermal, irrevesible compression of 1.00 mol of an ideal gas at 298K from 2.45x10^-3 atm to 2.45x10^-2 atm. d)Cconstruct the PV diagram for the processes described in part a,b, and c. e)Calculate the entropy change in the surroundings for the processes described in part a,b, and c. 9. Use the data from the thermochemical tables to calculate the boiling point (at P0 and at 0.500 P0) of CCl4. 10.One mole of an ideal gas with a volume of 6.67L and a pressure of 1.50 atm is contained in a vessel with a movable piston. The external pressure is suddenly increased to 5.00 atm and the gas is compressed isothermally ( T=122K). Calculate q,w, (delta E), (delta S), (delta H), (delta Ssurr), (delta Suniv), and (delta G). 11.Consider 1.00 mol of CO2(g) at 300K and 5.00 atm. The gas expands until the final pressure is 1.00 atm. For each of the following conditions describing the expansion, calculate (delta S), (delta Ssurr), and (delta Suniv). Cp for CO2 is 37.1J(K^-1)(MOL^-1), and assume that the gas behaves ideally. a) The expansion occurs isothermally and reversibly. b) The expansion occurs isothermally against a constant external pressure of 1.00 atm. c) The expansion occurs adiabatically and reversibly. PS. There was a sheet of thermochemical during the exam. PS. The following are the answers: 1. 1.6x10^-6(10pts) 2. the proof in on Zumdahl, Chemical principles, p457~458 r=5/3(10pts) 3. -100.81kJ(10pts) 4. -546kJ(4pts) -559.9kJ(4pts) 5. (I forgot)(3pts) 334.1K(3pts) 375.5K(3pts) 6. -31.853kJ(2pts) 3.81x10^5(2pts) 2.62x10^-6 atm(3pts) 7. -26.459 kJ(3pts) -3.225x10^3 kJ/mol(3pts) 3.226x10^3 kJ/mol(3pts) 8. Zumdahl, Chemical principles, 10-122 (6pts,6pts,6pts,3pts,3pts) 9. Tbp=347.9K(4pts) T=327.7K(4pts) 10.Zumdahl, Chemical principles, 10-108(10pts) 11.Zumdahl, Chemical principles, 10-86(6th edition) (5pts,5pts,5pts) There are 120 points on this test. Avr=54.7 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.7.59