精華區beta NTU-Exam 關於我們 聯絡資訊
課程名稱︰線性代數一 課程性質︰必修 課程教師︰林紹雄 開課系所︰數學系 考試時間︰2005/11/5 14:00~17:00 試題 :(註:「屬於」符號因BBS無法顯示,故改以中文寫出。) Math 201 14410-01 (Linear Algebra) Midterm Exam (11/5/2005) There are Problems A to D with a total of 110 points. Please write down your computational, or proof steps clearly on the answer sheets. A. Work out the following problems. (a)(20 points) Give the matrix [ 1 2 0 2 1 ] A = [-1 -2 1 1 0 ] [ 1 2 -3 -7 -2 ] Find a basis for the four fundamental subspaces of A, and determine their dimensions. Reduce A into a form PA=LU where P is a 3*3 permutation matrix, L is a 3*3 lower triangular matrix with unit diagonal, and U is a 3*5 row-echelon matrix. Write down explicitly all the pivots you use in the computation. (b)(20 points) Consider the square matrix [ 1 v1 0 0 ] A = [ 0 v2 0 0 ] [ 0 v3 1 0 ] [ 0 v4 0 1 ] (1) Factor A into LDU decomposition, and determine the condition that this matrix is invertible. -1 (2) When it is invertible, use Gauss-Jordan method to find its inverse A . When it is not invertible, do you need permutation matrix to reduce A into row-echelon form? (3) If A is not invertible, find its rand and nullity. Determine the 4 condition on the vector b 屬於 R such that Ax=b has at least one solution. B. Prove the following statements. (a)(7 points) Let A,B be square matrics. If I-BA is invertible, prove that -1 I-AB is invertible. Find (I-AB) explicitly. (b)(10 points) Let V be a vector space over a scalar field. If U,W 屬於 V are two finite-dimensional, and dim (U) + dim (W) = dim (U∩W) + dim (U+W) 2 (c)(7 points) Let A be a square matrix. Prove that the nullspace of A is 2 contains the nullspace of A, while the column space of A is contained in the column space of A. C. Determine which of the following statements is true or false. If true, prove it. If false, find a counterexample. Each has 6 points. (a) If the column vectors of a matrix are independent, the its row vectors are also independent. (b) There exists a 3*2 matrix A such that two 2*3 matrices B and C exist, and satisfy AB=I_3 and CA=I_2 2 2 2 (c) For two square matrices A,B, (AB) =A B iff AB=BA (d) Let V be a vector space. f:V→V and g:V→V are two linear transformations. If g(f(v))=2v for all v 屬於 V, then f is one-to-one and onto. 4 (e) Every subspace of R is the nullspace of some matrix. (f) The matrix A has the LU decomposition [ 1 0 0 0 ][ 1 2 0 1 2 1 ] A = LU = [ 2 1 0 0 ][ 0 0 2 2 0 0 ] [ 2 1 1 0 ][ 0 0 0 0 0 1 ] [ 3 2 4 1 ][ 0 0 0 0 0 0 ] Then columns 1,3,6 of U are a basis for the column space of A. m D.(10 points) If a symmetric square matrix A satisfy A =0 for some positive integer m, prove that A=0. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.240.198