精華區beta NTU-Exam 關於我們 聯絡資訊
課程名稱︰線性代數 課程教師︰林紹雄 開課學院:理學院 開課系所︰數學系 考試日期(年月日)︰2007 11 11 考試時限(分鐘):180 是否需發放獎勵金:是 試題 : 130 points. A. Consider the matrix [0 0 1 -3 2] A=[2 -1 4 2 1] [4 -2 9 1 4] [2 -1 5 -1 5] (a) 15 points Find its LDU-decomposition in the form PA=LDU.Write down explicitly all the pivots you use in the computation. (b) 10 points From the form of (a),write down a basis for the four foundamental subspaces of A.Determine its rank and nullity. (c) 10 point Consider the system of equations Ax=b for b屬於R^4.Which variable in x are pivot variables,or free variables?Find the consistency conditions for b so that Ax=b has at least one solution,and find all its solutions. B. 20 points Consider the matrix [1 v1 0 0] A=[0 v2 0 0] [0 v3 1 0] [0 v4 0 1] where v1 v2 v3 v4 are four given real numbers. Apply the Gauss-Jordan method to find the condition that A is invertible,and find its inverse explicitly. When A is not invertible,find the dimentions of its four foundamental subspaces. C. Let the subspace V of R^4 be spanned by the following vectors v1=[1 -1 0 0]^T v2=[1 0 -1 0]^T v3=[1 0 0 -1]^T v4=[0 1 -1 0]^T v5=[0 1 0 -1]^T v6=[0 0 1 -1]^T (a) 10 points Find the dimension of V, and extract a basis of V from these vectors (b) 15 points Find a linear transformation T:R^4→R^5 so that its range space T(R^4) is the subspace of R^5 defined by the system of equations x1+3x2-2x4+x5=0, x2-x3-x4+5x5=0 and T satisfies V∩ker(T)={0} and V∪ker(T)=R^4 Write down the matrix representation of T with respect to the natural basis of R^4 and R^5. D.Prove th following ststements. (a) 8 points Let A,B be two n*n matrices.If In-BA is invertible,prove that In-AB is invertible.Find (In-AB)^-1 explicitly. (b) 10 points Let V be a finite-dimensional vector space.W包含於V is a subspace. Proce that dim(V/W)=dim(V)-dim(W) (c) 8 points Let A,B be m*n and n*k matrices respectively.If AB=0,prove that rank(A)+rank(B)≦n.Can the equality be achieved? E. Determine which of the following statement is true.Prove your answer,or give a counterexample.Each has 6 points. (a) The column vectors of square matrix are linearly independent iff its row vectors are linearly independent. (b) Let V be a vector space. S,T:V→V are two linear transformations.If T(S(v))=100v for all v屬於V,then T is one-to-one and onto. (c) The matrix A has the LU-decomposition [1 0 0 0] [1 2 0 1 2 1] A=LU=[2 1 0 0]* [0 0 2 2 0 0] [2 1 1 0] [0 0 0 0 0 1] [3 2 4 1] [0 0 0 0 0 0] Then the columns1,3,6 of U are a basis for the column space of A (d) Let A be a m*n real matrix.THen the rank of A achieve the maximum possible rank iff either (A^T)A or A(A^T) is invertible. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.242.210