[Ｃ++] 上機第七題(可解虛根)

[sb0917 (バカ)]

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
        double a,b,c,d;

        cout << "ax^2+bx+c=0 Please input a,b,c.\na= ";
        cin >> a;
        cout << "b= ";
        cin >> b;
        cout << "c= ";
        cin >> c;

        d = b*b-4*a*c;

        if(d>0)
        {
                cout << "x1= " << (-b+sqrt(d))/(2*a) << endl;
                cout << "x2= " << (-b-sqrt(d))/(2*a) << endl;
        }
        else if(d==0)
                cout << "x1=x2= " << -b / (2*a) << endl;
        else
        {
                cout << "x1= " << -b/(2*a) << "+" << sqrt((-d))/(2*a) << "i" << endl;
                cout << "x2= " << -b/(2*a) << "-" << sqrt((-d))/(2*a) << "i" << endl;
        }

        system("pause");
        return 0;
}


明明才多幾行...加一下咩...

a = 0的話一定爆喔...

輸入你家的工程計算機a=0他一樣會說math error...

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