作者chieh0206 (ming chieh)
看板NTUBIME102HW
標題[普物] 橫波那題
時間Wed Jan 13 01:18:44 2010
Y1=Asin(kx-wt)
Y2=Asin(kx+wt+Q)
Y1+Y2=2Asin(kx+Q/2)cos(wt+Q/2)
帶入 X=d
=> kd+Q/2=0 or pi or 2pi ......
=> Q=-2kd
所以 Y2=Asin(kx+wt-2kd) ...#
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