精華區beta NTUBIME102HW 關於我們 聯絡資訊
力矩 = mgLsin(Q) + F*h = mgL*Q + (khQ)*h = m(L^2)*a (ps:a為角加速度) => w^2 = (mgL+kh^2)/(mL^2) => T = 2pi*((mL^2)/(mgL+kh^2))^0.5 ......# -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.242.142
ansonyu:有神快拜!!!!!!!!!!!! 01/13 01:27
chieh0206: Q 是角度!!! 01/13 01:27
sdg85732:謝謝囉!! 真的太佩服了!! 01/13 01:29
tony80517:強者!!!! 01/13 01:30