精華區beta TransPhys 關於我們 聯絡資訊
Three moles of an ideal gas undergo a reversile isothermal compression at 20C. During this compression, 1850J of work is done on the gas. What is change of entropy of the gas? 應該是-1850/293對吧 可是Young的解答寫1850/293耶 是我錯了嗎? 謝謝^^ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 125.226.48.230
weakaday:因為氣體是吸熱,所以Q取正~~~~ 05/30 10:54
pobm:可是被壓縮是外界對氣體作功耶 05/30 13:24
pobm:1850J of work is done on the gas.是不是我文法太爛~~ 05/30 13:24
pobm:我看起來他好像是在說氣體被做功1850J 05/30 13:25
weakaday:這句翻出來似乎是1850J的功被做在氣體上...我英文也很破 05/30 16:07
weakaday:pobm你的答案應該是對的,解答可能有錯 05/31 09:54
weakaday:我之前忘記考慮熱力學第一定律了 05/31 09:58
> -------------------------------------------------------------------------- < 作者: axis0801 (時和空的流轉) 站內: TransPhys 標題: Re: [熱能] 等溫壓縮 時間: Thu May 31 01:59:22 2007 ※ 引述《pobm (待從頭收拾舊河山)》之銘言: : Three moles of an ideal gas undergo a reversile isothermal compression : at 20C. During this compression, 1850J of work is done on the gas. : What is change of entropy of the gas? : 應該是-1850/293對吧 : 可是Young的解答寫1850/293耶 : 是我錯了嗎? : 謝謝^^ 題目指出是可逆等溫壓縮  所以是外界對系統作功,這樣系統一定要 "放熱",不然內能就會改變    等溫壓縮 => Q = -W = -1850 (J)   這是我的想法,僅供參考!   -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.62.121.187
pobm:謝謝^^ 06/05 01:24