精華區beta ck54th310 關於我們 聯絡資訊
※ 引述《idernest (..)》之銘言: 不錯....有進步... : ※ 引述《gwogwo (要專心唸書不能玩)》之銘言: : : find an equation of the tangent to the given curve at the given point!! : : x*sin(xy-y^2)=x^2-1 at(1,1) : Implicit differentiation??? : Actually, it's not so hard..... : If my calculation is correct, the answer will be : dy [2x- Sin(xy-y^2) - xy Cos(xy - y^2)] | : -- = --------------------------------------| = -1 : dx (x^2-2xy) Cos(xy-y^2) |(1,1) : So the answer is x + y = 2 ?? : Or is it still not a correct answer? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.7.59