[問題]startActivityForResult搭配onBackPressed

[kdok123 (小天)]

A.class
onCreate:
{
                Intent intent = new Intent("test1");//會跳到B.class
                Bundle bundle = new Bundle();
                bundle.putString("toB", "toB");
                intent.putExtras(bundle);
                startActivityForResult(intent, 1);
}
    protected void onActivityResult(int requestCode, int resultCode, Intent
data) {
        super.onActivityResult(requestCode, resultCode, data);

        switch (requestCode) {
            case 1:
                if (resultCode == RESULT_OK) {
                    String returnValue = data.getExtras().getString("toA");
                    Log.e("onActivitiyResult", returnValue);
                }
                break;
            default:
        }
    }
-----------------------------------------------------------------------------
B.class
    public void onBackPressed() {
        super.onBackPressed();
        Intent intent = getIntent();
        Bundle bundle = intent.getExtras();
        Log.e("Act2", ""+bundle.getString("toB"));
        bundle.putString("toA","toA");
        intent.putExtras(bundle);
        setResult(RESULT_OK, intent);
        finish();
    }

我如果把這個fun寫在B.class的onCreate，A.class的onActivityResult就找得到

但寫在onBackPressed()就無法

但我希望使用者從A跳到B時，若按了Back鍵可以回傳值，應該要寫在這沒錯吧?

請問是哪個地方出問題了呢?

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→ c910335: 去掉super.onBackPressed();
→ kdok123: 真的欸!(這句快變我的口頭禪了)
→ kdok123: 另外把super.onBackPressed()放在最後面也可
→ ssccg: 原本的back處理是 回復actionbar > pop fragment > 關activ
→ ssccg: ity，如果自訂的流程就是要finish，那再呼叫super的沒意義.