推 jamielo: 咦，不對嗎？-_- 11/16 00:16
→ xiaoa: 25% SCD患者存活至生育, 是不是表示 >=25% 11/16 12:03
→ xiaoa: 而relative fitness 91% = genotype的frequency嗎? 11/16 12:04
【問題】：Sickle cell disease (SCD) is found in numerous populations whose ancestral
homes are in the malaria belt of Africa and Asia. SCD is an autosomal
recessive disorder that results from homozygosity for a mutant β-globin gene
allele. Data on one affected population indicates that approximately 4 in 100
newborn infants have SCD.
Epidemiologic data on the population in the previous problem reveal that
before the application of modern medical treatment, natural selection played
a major role in shaping the frequencies of alleles. Heterozygous individuals
have the highest relative fitness; and in comparison to heterozygotes, those
who are βAβA have a relative fitness of 91 percent, but only about 25
percent of those with SCD survived to reproduce.
What is the estimated equilibrium frequency of βA in this population?
What is the estimated equilibrium frequency of βS in this population?
【問題起因】：mastering genetics
【個人看法】：
q^2=0.25-->q=0.5 ( βS in this population)
2pq=0.91-->p=0.91/2*0.5 (βA in this population)
答案是錯的
有人知道怎們做嗎?謝謝
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