推 trees880098 : 收化學系 01/14 06:02
課程名稱︰分析化學一
課程性質︰必修
課程教師︰何國榮
開課學院：理學院
開課系所︰化學系
考試日期（年月日）︰103/11/17
考試時限（分鐘）：110分鐘
試題 :
Analytical Chemistry
11/17/2014
ID: Name:
Briefly answer the following question (100%)
1. List the major qualities of analytical results. (6%)
2. Explain the needs of (a) sampling and (b) sample preparation. (8%)
3. In ANOVA, explain the reason of using variance for comparing the means more
than two population. (6%)
4. Explain the importance of traceability. (5%)
5. Describe the assumtion for the correctness of the following equation. (5%)
6. Explain the similarity and difference between accuracy and trueness. (6%)
7. Describe the advantage of pooling data to obtain S. (5%)
8. Describe the precedure to detect systemetic error if a standard reference
material (SRM) is not available. (6%)
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9. With the equation of x ±ts/√N, explain that N is not necessary larger than
3 if s is estimated externlly. (5%)
10.In the calculation of standard uncertainly due to systemic error, explain
that √3 was used in the calculation of molecular weight of C2H4. √6 was
used in volumetric pipette. (6%)
11.Explain that two-tailed t table if often used in one-tailed t test. (5%)
12.For the comparison of two means, explain that F test should be performed
before the t test. (5%)
13.In paired t-test, explain that the comparing two means is not appropriate.
(5%)
14.Explain the β error of method detect limit (M.D.L.) (5%)
15.List the equations related to calculation of R^2. (6%)
16.Explain that isotope internal standard is often used in mass spectrometry
related analysis. (5%)
17.Explain that standard addition can be used to overcome matrix effect. (5%)
18.The solubility product K_sp for the silver salt AgX is 4.0(±0.4)x10^-8.
Calculate solubility of AgX. (6%)
Bonus (10 points)
1. In ANOVA, the following equation is used to calculate the least significant
difference. LSD = t√(2xMSE/Ng), Ng: equal number of replicate in each group.
Explain the reason of including 2 in the equation. (5%)
2. Please derive the equation for the standard deviation of the mean, s/√n (5%)
http://ppt.cc/vfWT
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