[規則] Gloomhaven修正牌的優勢選取

[Greatsea (小左)]

剛好最近在研究這個規則,又剛好有版友問到我這個規則.
我們這一團有人在BGG上看到這個答案,就PO出來跟Gloomhaven的愛好者分享
(之前也受過其他版上大大的幫助,非常感恩,來回饋一點,希望能幫上忙)
PS 僅管玩了100小時,還是有很多規則我們這團一直在更新....

修正牌堆
如果角色進入優勢狀態,會抽二張,並選取好的.
帶有其他狀態(stun.產元素)的修正卡,視為正值但無法計算價值
無法辦別時,則 ""選取第一張""

碰到修正卡""帶有狀態,難以辦別"",這個規則,很難懂....

+1 VS +2 = 選+2

+1 帶出 +0 VS +2 = 選+2

+1 VS +產元素 +1 = 選+產元素 +1

+0 Stun vs +2 = ??

+1 Stun vs +1 Fire = ??

+0 Muddle vs +2 Stun = ??



-----以下片段取自BGG,此篇為作者Isaac Childres回應-------


https://boardgamegeek.com/thread/1719142/advantagedisadvantage-better-card-and
-e


Sorry, I didn't respond here because I thought it had been resolved by the
rules. If it is ambiguous, use the first card. But I see you are having
trouble determining what is ambiguous. If you want to get techincal, I guess
you could say that all added effects (conditions or elements or whatever)
have a positive but undefined value. Thus, these would be the rulings in the
following cases:

+1 vs +2: +2 is better
+1 Stun vs +1: +1 Stun is better
+0 Stun vs +2: Ambiguous
+1 Stun vs +1 Fire: Ambiguous
+0 Muddle vs +2 Stun: Ambiguous

You could argue that some conditions are better than others, but that would
require giving each of them values or creating an intricate hierarchy, which
would go against the design philosophy of keeping things as simple as
possible. Plus, everything is situational, so an effect that might be better
in one case wouldn't be better in another. So the official ruling is that
every added effect is positive but undefined. Hopefully that clears things up.


-----------------------

答案是:
全數選第一組

+0 Stun vs +2 = +0 Stun

+1 Stun vs +1 Fire = +1 Stun

+0 Muddle vs +2 Stun = +0 Muddle




再另一個分享:

如果劣勢選差的,碰到一堆帶牌可以繼續翻牌呢?

所有的帶牌都視為取消多抽的牌,完全不選
接下來抽到的牌,或是一開始抽到的牌,就是直接選取
這個就可以直接看規則書上的範例

luslus大大解說：
1) 劣勢抽到roll跟非roll，判定是只有那張非roll 
2) 劣勢抽到2張roll，補牌補到非roll，判定是最後那張非roll



提到這二個問題
是因為我腦殘的帶著大家玩錯很久很久很久.....
並且相關修正牌的規則,總共改了三次到現在,才勉強應該算是玩正確

歡迎大家一起討論分享,如果有說錯,請直接指正,玩對規則才是最重要的事情.
當然....沒有困擾到您,是最好的.....


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※ 文章網址: https://www.ptt.cc/bbs/BoardGame/M.1525366973.A.EB3.html
→ tony332976: 在外面 第二個問題其實有比較好記的方法 晚點回文
→ Greatsea: <3
→ luslus: 二版在優劣勢抽到roll牌解法跟1版不同呢
→ luslus: 優勢抽到1張roll 1張非roll = 這次判定就用這兩張
→ luslus: 優勢兩張都roll，補牌補到非roll，判定是抽出來的每張牌
→ luslus: 劣勢抽到roll跟非roll，判定是只有那張非roll
→ luslus: 劣勢抽到2張roll，補牌補到非roll，判定是最後那張非roll
謝謝解說<3
※ 編輯: Greatsea (1.200.210.200), 05/04/2018 17:14:18
推 LiouKen: 感謝luslus，不過這樣優勢的判斷還是稍嫌繁複
→ luslus: 有roll的優劣勢會很自然的想抽出兩敦結果判定好壞
→ luslus: 但規則已經說了，就是抽兩張直接解效果
→ luslus: 另外，如果抽出的兩張 帶不同狀態，會判定為未定義好壞
→ luslus: 這個時候規則會強制選擇第一張為結果
→ luslus: bgg其實因為這個roll與優劣勢一直有人在爭論(?
→ luslus: 因為roll +1跟null在優勢時一起抽出來就會變成null
→ luslus: (但是反過來說，劣勢抽到+1 roll跟2倍 就是2倍)
→ luslus: 其實比起roll跟優劣勢的判定，怪物的focus配上遠距離和
→ luslus: 多目標(可能再加上陷阱地形)會很難解判定