推 IvanL: 畫線段長短就可以~不用使用到未知數~ 11/27 14:37
推 binbinthink: AD比CF多2/5 ===> AC比DF多2/5 ===> 11/27 15:37
→ binbinthink: AB+13/5比DF多2/5 ===>AB+11/5與DF等長 11/27 15:38
→ binbinthink: 但AB比EF少7/10 ===>所以11/5只好比DE多7/10 11/27 15:39
→ binbinthink: 所以DE=11/5-7/10=3/2 11/27 15:39
推 vipg5: AD=AB+BC+CD CF=CD+DE+EF 根據題目AD=CF+2/5 11/28 00:01
推 vipg5: AB+BC+CD=CD+DE+EF+2/5 >>>>> AB+13/5=DE+EF+2/5 11/28 00:05
推 ukalm: 每段用代號,看懂(EF-AB)+(AD-CF)=11/10剩下就代代號進去 11/28 01:22
→ ukalm: 就會抵銷只剩題目所求那段了.. 11/28 01:23
推 blueskylover: 之前算,今天用到,感謝分享~ 12/11 00:39