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抱歉,小弟底子實在是太差了 不把 template 和 operator 的 overload 搞定根本很難看 android 的 code... #include<iostream> #include<stdlib.h> using namespace std; template<typename T> class Demo{ public: inline Demo():m_ptr(0){ cout<<"This is the First constructor "<<endl; } Demo(T* other); Demo(const Demo<T>& other); //Assigment Demo& operator = (T* other); //Accessors inline T* operator-> () const { return m_ptr; } inline T& operator* () const { return *m_ptr; } private: T* m_ptr; }; template<typename T> Demo<T>::Demo(T* other){ cout<<"This is the Second constructor"<<endl; } template<typename T> Demo<T>::Demo(const Demo<T>& other){ cout<<"This is the Thirdth constructor"<<endl; } class myClass{ public: myClass(); }; int main(){ Demo<myClass> d; myClass *mptr = 0; //我該如何使用 Demo 類別的 Assigment 和 Accessors 呢? cout << *d <<endl; //error d = *mptr; //error d.operator*(mptr); //error } 感謝指教... -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 58.115.110.72 ※ 文章網址: https://www.ptt.cc/bbs/C_and_CPP/M.1460809755.A.8C6.html
bibo9901: m_ptr 是 0 當然會error 04/16 20:33
Frozenmouse: 應該是 d = mptr 吧,參數型態是myClass* 04/16 20:34
bibo9901: 然後問問題時最好講清楚"error"是compile error還是 04/16 20:34
bibo9901: runtime error, 最好把錯誤訊息也寫出來 04/16 20:35