推 sonesnsdsosi: 有點不太清楚你想表達的意思 可以做個示意圖(表)嗎? 02/10 16:37
→ sonesnsdsosi: 光看字面的意思,select distinct name from table 02/10 16:38
→ sonesnsdsosi: where date='當天日期'; 是否達到你要的? 02/10 16:39
※ 編輯: silent910 (111.80.199.107), 02/10/2015 17:45:31
推 sonesnsdsosi: 首先,你的欄位date的名字我改成dates,方便後續操作 02/11 08:36
→ sonesnsdsosi: 語法select distinct to_char(dates,'yyyy/mm/dd') 02/11 08:37
→ sonesnsdsosi: "date",id,name from yourtable; 02/11 08:38
→ sonesnsdsosi: 如果你的順序要是 id name date,那我再加個子查詢 02/11 08:39
→ sonesnsdsosi: select id,name,dates from (select distinct 02/11 08:39
→ sonesnsdsosi: to_char(dates,'yyyy/mm/dd ')dates,id,name from 02/11 08:39
→ sonesnsdsosi: yourtable); 希望有幫助到你 02/11 08:40
→ silent910: 謝謝您!! 02/14 11:21
推 cdanyu: select distinct id, name, convert(char(7), date, 111) 02/23 00:18
→ cdanyu: from table_name 02/23 00:18
→ cdanyu: 應為 convert(char(9), date, 111) 才對。 02/23 00:52