看板 IMO_Taiwan 關於我們 聯絡資訊
1. Triangle BCF has a right angle at B. Let A be the point on line CF such that FA=FB and F lies between A and C. Point D is chosen so that DA=DC and AC is the bisector of ∠DAB. Point E is chosen so that EA=ED and AD is the bisector of ∠EAC. Let M be the midpoint of CF. Let X be the point such that AMXE is a parallelogram. Prove that BD,FX and ME are concurrent. 2. Find all integers n for which each cell n*n table can be filled with one of the letters I,M and O in such a way that: ‧in each row and each colume, one third of the entries are I, one third are M and one third are O; and ‧in any diagonal, if the number of entries on the diagonal is a multiple of three, then one third of the entries are I, one third are M and one third are O Note: the roes and columns of n*n table are each labelled 1 to n in a natural order. Thus each cell corresponds to a pair of positive integer (i,j) with 1≦i,j≦n For n>1, the table has 4n-2 diagonals of two types. A diagonal of 1st type consists all cells (i,j) for which i+j is constant. A diagonal of 2nd type consists all cells (i,j) for which i-j is constant. 3. Let P = A1A2...Ak be a convex polygon in the plane. The vertices A1,A2,...,Ak have integral coordinates and lie on a circle. Let S be the area of P. An odd positive integer n is given such that the squares of the side lengths of P are integers divisible by n. Prove that 2S ia an integer divisible by n. -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 114.47.128.188 ※ 文章網址: https://www.ptt.cc/bbs/IMO_Taiwan/M.1468224493.A.7E5.html