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請問各位在unix有什麼比較好的方法用shell script可以比較兩個檔案中第其中一欄位的值.兩個檔案會 1:每行所含的資料順序不一定一樣,有資料在檔案A出現在檔案B不一定出現 2:想比較第三欄(yes, no,empty)的值 如 File A: $cat A.log case1,0.0001,yes case2,0.0021,no case3,0.0041,no case4,0.0041,empty case5,0.0101,empty case6,0.0501,yes File B: $cat A.log case1,0.0001,yes case7,0.0021,yes case2,0.0041,yes case3,0.0041,empty 希望output: case2 no yes:case3 no empty:case4 empty " ":case5 empty " ":case6 yes " ":case7 " " yes. -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 72.80.104.128 ※ 文章網址: https://www.ptt.cc/bbs/LinuxDev/M.1447124344.A.D81.html
redshoe: sed,sort ,diff,awk,pipe ? 11/11 11:10
kerwinhui: 先sort再用join的-o 11/11 12:44
jacobcan118: 感謝 sort + join有用 11/12 12:22