看板 MacDev 關於我們 聯絡資訊
今天嘗試用Swift解難度6級的Floating-point Approximation (I): https://www.codewars.com/kata/58184387d14fc32f2b0012b2 結果只有測試資料Pass, 傳送過去就Fail了。 想了一個下午,最後只好看解答, 看了解答,我還是想不出來…為什麼?有人能明講, 這題解答的原理是什麼嗎? 題目很短,我順便Po在下面: Consider the function f: x -> sqrt(1 + x) - 1 at x = 1e-15. We get: f(x) = 4.44089209850062616e-16 or something around that, depending on the language. This function involves the subtraction of a pair of similar numbers when x is near 0 and the results are significantly erroneous in this region. Using pow instead of sqrt doesn't give better results. A "good" answer is 4.99999999999999875... * 1e-16. Can you modify f(x) to give a good approximation of f(x) in the neighborhood of 0? Note: Don't round or truncate your results. See the testing function in Sample Tests:. -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 1.161.9.149 (臺灣) ※ 文章網址: https://www.ptt.cc/bbs/MacDev/M.1670930622.A.315.html
pmove: 我想出來了,只用到簡單公式,(x+1) * (x- 1.161.9.149 12/13 20:49
pmove: 1) = x^2 - 1 ,討論區還有人說要用到泰勒 1.161.9.149 12/13 20:49
pmove: 展開式…笑死 1.161.9.149 12/13 20:49
pmove: 這題拿去問New Bing, 它可以解的出來喔,只 1.161.38.179 03/26 10:12
pmove: 是程式碼累贅了一點 1.161.38.179 03/26 10:12