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※ 引述《kyoiku (生死間有大恐怖)》之銘言: : f(x) = / -1, -pi <= x < 0 : \ 1, 0 <= x <= pi : (a) Find the Fourier series of f(x) on [-pi , pi] n = 0 a_0 = 0 n > 0 π a_n = (1/π)∫f(x) cos(nx) dx -π = (1/π) 0 π b_n = (1/π) ∫f(x) sin(nx) dx -π π = (2/π) (-cos(nx))/n | 0 = (2/π) [(-1)^(n+1) + 1]/n ∞ f(x) = Σ 4/[π(2k+1)] * sin((2k+1)x) k=0 : (b) Use (a) to find the sum of the series : 1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 +-...... 原式 = (π/4)f(π/2) = π/4 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 220.141.64.244 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1421212923.A.C19.html
kyoiku : 謝啦 01/14 16:10