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Let G be a connected and simply connected algebraic group over real field or complex field, and let H be a closed subgroup of G. Denote by H' the universal covering group of H, and then the inclusion i:H->G gives an inclusion d(i):h->g of their corresponding Lie algebras. Hence, d(i) is lifted to an injective homomorphism i':H'->G. Moreover, i*p=i' where p is the covering map from H' to H. Since i' is injective, it follows that p must be injective, and so p is isomorphism. Therefore H is isomorphic to H' which is simply connected. This shows that any closed subgroup of a simply connected algebraic group is simply connected. However, set G=SL(n,C) and H=SO(n,C). Then G is simply connected, but H is not. 我想了很久, 沒有想出來自己的推理有甚麼問題. 請問為甚麼會出現矛盾呢? 求高人解答. 不勝感激! -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 180.154.50.218 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1422289988.A.4CE.html ※ 編輯: WasabiSushi (180.154.50.218), 01/27/2015 00:35:27
kerwinhui : H' -> G not injective, easier eg: S^1 -> C* 01/27 01:25
WasabiSushi : 抱歉, C*=C-{0}不是simply connected的. 01/27 21:46
kerwinhui : Oops, try S^1 -> SU(2); z |-> diag(z,z^*) 01/28 18:37
kerwinhui : Or: maximal torus in s.c. Lie group 01/28 18:46
WasabiSushi : Thanks. As to your example, S^1=SO(2)->SU(2) is 01/29 02:30
WasabiSushi : lifted to Spin(2)->SU(2). Do you mean that this 01/29 02:32
WasabiSushi : is not injective? 01/29 02:33
kerwinhui : Spin(2)->SO(2) is z|->z^2, Spin(2) is not s.c. 01/29 07:14
kerwinhui : Spin(2)->SU(2) has kernel ±1 01/29 07:16
WasabiSushi : Sorry,I'm a bit confused.The fundamental group 01/29 13:57
WasabiSushi : of S^1 is Z,so the kernal of the covering map is 01/29 14:02
WasabiSushi : Z instead of {1,-1}.Actually,Spin(2) is just 01/29 14:06
WasabiSushi : isomorphic to R*.But what makes me fell strange 01/29 14:08
WasabiSushi : is that the Lie algebra injection R->su(2) 01/29 14:12
WasabiSushi : given by x|->diag(ix,-ix) doesn't lift to a 01/29 14:18
WasabiSushi : group homomorphism. 01/29 14:18
kerwinhui : No! Spin(2) is the unique double cover of SO(2) 01/29 14:29
kerwinhui : and exponentiating from algebra to group does 01/29 14:30
kerwinhui : not preserve injection. 01/29 14:31
kerwinhui : otherwise there would be no maximal tori, a huge 01/29 14:31
kerwinhui : blow to much of Lie theory 01/29 14:32
WasabiSushi : Oh,you are right.Spin(2) is not the universal 01/29 15:14
WasabiSushi : cover.Yes,exponentiating does not preserve 01/29 15:20
WasabiSushi : injection. Thank you so much! 01/29 15:21