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※ 引述《JohnMash (Paul)》之銘言: : 令 : Λ_k(n) = Σ_{d|n} μ(d) ( ㏒(n/d))^k : 試證 : 當 n 的質因數個數大於k時 Λ_k(n) = 0 let L represent the function log then, by definite, Λ_k = μ*(L^k), where * means convolution. Clearly, the Mangoldt function Λ=Λ_1 = μ*L =L.(μ*1) - (μL)*1 = (-μL)*1 Now, use (log(n/d))^k = (log(n/d)^{k-1})(log n - log d), we see that Λ_k = L.Λ_{k-1} + (-μL)*L^{k-1} = L.Λ_{k-1} + (μ*Λ)*L^{k-1} = L.Λ_{k-1} + Λ*Λ_{k-1}. Hence the result. -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 118.165.202.75 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1423769327.A.22E.html
JohnMash : Great 02/13 11:39