推 JohnMash : Great 02/13 11:39
※ 引述《JohnMash (Paul)》之銘言:
: 令
: Λ_k(n) = Σ_{d|n} μ(d) ( ㏒(n/d))^k
: 試證
: 當 n 的質因數個數大於k時 Λ_k(n) = 0
let L represent the function log
then, by definite, Λ_k = μ*(L^k), where * means convolution.
Clearly, the Mangoldt function Λ=Λ_1 = μ*L
=L.(μ*1) - (μL)*1
= (-μL)*1
Now, use (log(n/d))^k = (log(n/d)^{k-1})(log n - log d),
we see that Λ_k = L.Λ_{k-1} + (-μL)*L^{k-1}
= L.Λ_{k-1} + (μ*Λ)*L^{k-1}
= L.Λ_{k-1} + Λ*Λ_{k-1}.
Hence the result.
--
※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 118.165.202.75
※ 文章網址: https://www.ptt.cc/bbs/Math/M.1423769327.A.22E.html