→ binbinthink : 角C=60度=>弧AEB=120,減弧AE90得弧EB=30度 02/14 11:47
→ binbinthink : 弧EB=30可繼續推得角OBC=30度~故OB:1/2BC=2:根號3 02/14 11:49
→ binbinthink : EF=2OB故EF:BC=2:根號3 02/14 11:49
→ binbinthink : 設OD與BC交於G,角OBC=30度故OG=1/2OB 02/14 11:51
→ binbinthink : 得AO:AG=2:3==>三角形上面那塊:三角形ABC=2^2:3^2 02/14 11:52
→ binbinthink : =4:9,故上面那塊:下面那塊應該是4:5,並不平分 02/14 11:52
→ hoodlumcrow : 感謝B大!豁然開朗了! 02/14 12:07
→ s00459 : AD為BC中垂線,BO=AO=EO,又BO:DO=2:1,得EF:BC=2:√3 02/14 14:44
→ s00459 : EF//BC,AO:AD=2:3,得面積比為4:9,故(D)應為4:5 02/14 14:46
→ s00459 : ^^應該是AD跟BC的交點 02/14 14:47