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f(x) = 2x^3 + a(a+3)x^2 - 2x + (2b-a) f(0) = 2b -a > 0 => 2b > a f(1) = f(-1) = a(a+3) + (2b-a) = a^2 + 2a + 2b = 0 => 2b = -a^2 - 2a > a => 0 > a(a + 3) => -3 < a < 0 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 114.44.219.104 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1425174312.A.B01.html