作者a016258 (憨)
看板Math
標題Re: [中學] 高中數學
時間Mon Nov 2 18:56:41 2015
※ 引述《semmy214 (陳山河)》之銘言:
: http://imgur.com/YAUm71e
: 第1題不用回答
: 2、3、4煩請版上高手解答
2. θ 省略... sin^m = ( sin θ)^m
x^2 + y^2 = cos^6 + (sin^6 + 2sin^4 + sin^2) (三次方和 拆 前兩項)
= (cos^4 - cos^2 sin^2 + sin^4) + 2sin^4 + sin^2 (合併二、五項)
= cos^4 + 4 sin^4
= (cos^2 + 2sin^2 )^2 - 4sin^2 cos^2
= sin^4 + 2sin^2 + 1 - 4sin^2 cos^2
= sin^4 + 2sin^2 + 1 - 4sin^2 (1 - sin^2 )
= 5sin^4 - 2sin^2 + 1
= 5( sin^2 - (1/5) )^2 + 4/5
when sin^2 = 1/5 , min = 2/√5
when sin^2 = 1 , max = 2
4. f(x) = sinx cosx + a(sinx + cosx) + a^2 ( t = sinx + cosx ≦ √2 )
= (t^2 - 1)/2 + at + a^2
= (1/2) (t^2 + 2at + 2a^2 - 1) ( ∵ a ≧ 0 )
≦(1/2) ( 2 + 2√2 a + 2a^2 - 1)
= (1/2) (2a^2 + 2√2 a + 1) = 25/2
=> a^2 + √2 a - 12 = 0
-√2 + √50
a = --------------- = 2√2
2
有錯還請不吝指正。
--
If people do not believe that mathematics is simple,
it is only because they do not realize how complicated life is.
- John von Neumann
--
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※ 編輯: a016258 (140.114.137.240), 11/02/2015 19:03:32
→ semmy214 : (cos^4 - cos^2 sin^2 + sin^4) 這地方不懂 11/02 19:04
cos^6 + sin^6 = (cos^2 )^3 + (sin^2 )^3 三次方和化成兩項相乘
※ 編輯: a016258 (140.114.137.240), 11/02/2015 19:06:27
→ semmy214 : a^3+b^3 不是(a+b)(a^2-ab+b^2) 好像漏了(a+b) 11/02 19:10
(a+b) = ?
→ Eliphalet : semmy214 你展開就好了,不會費你太多時間 11/02 19:16
→ semmy214 : E大謝了 我懂了~ 11/02 19:32
→ semmy214 : 第4題.第3行跳第4行不懂... 11/02 19:43
→ semmy214 : 剛剛看懂了 但為什麼sinx+cosx小於根號2 11/02 19:45
→ Eliphalet : 疊加 sin(x)+cos(x) = √2 sin(x+π/4) 11/02 20:28
※ 編輯: a016258 (218.161.70.138), 11/02/2015 20:34:14