→ Eliphalet : 可以先化簡成 3ln(4) + 3 ln(ln(x)) 比較不會計算 03/22 13:27
→ Eliphalet : 錯誤 03/22 13:27
→ shingetsu : 答案寫 3/x ln x 錯了嗎 03/22 14:58
推 sunev : 分母 ln(x^4)換成 4l n(x)就一樣了 03/22 15:23
→ shingetsu : 謝謝! 沒注意到 03/22 19:59
※ 引述《shingetsu (shingetsu)》之銘言：
: Find the derivative of ln[(ln x^4)^3]
ln[ ln(x^4)^3 ]' = 1/(ln(x^4)^3) * [ln(x^4)^3]'
= 1/(ln(x^4)^3) * 3*ln(x^4)^2 * [ln(x^4)]'
= 1/(ln(x^4)^3) * 3*ln(x^4)^2 * 1/x^4 * [x^4]'
= 1/(ln(x^4)^3) * 3*ln(x^4)^2 * 1/x^4 * 4x^3
= 12x^3*ln(x^4)^2 / (x^4*ln(x^4)^3)
= 12 / (x*ln(x^4))
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※ 編輯: softseaweed (97.90.206.74), 03/22/2016 13:27:05