→ Honor1984 : EF = 3 => DJ = 6 => AE = 12 => AF = 9 06/06 11:43
※ 引述《yizihappyQ (Ms.Q)》之銘言:
: http://i.imgur.com/TnUYBW0.jpg
: 請問左上第8題怎麼解?
: 謝謝!
過D做AE平行線交BC於J
=> BJ = JE
DFEJ = 5 * 4 - 5 = 15
△DFE = △CFE = 5
=> △DJE = 15 - 5 = 10
=> △DJE = △BJD = 10
=> BEFD = 10 + 15 = 25
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