Re: [中學] 餘式定理

[Honor1984 (喬祺對我如此狠)]

※ 引述《blackymys (mys)》之銘言：
: 求教第11題解題過程，謝謝。
: http://i.imgur.com/AXO9eEE.jpg

f(x) = (x - 1)^3 [px + b] + 3

     = (x - 2 + 1)^3 [px + b] + 3

     = (x - 2)*... + [px + b + 3]

     = (x - 2)*... + b + 3 + 2p

=> b + 2p = 3

同理

f(x) = (x + 2 - 3)^3 [px + b] + 3

     = (x + 2)*... [-27px + (3 - 27b)]

     = (x + 2)*... + [-27b + 54p + 3]

=> 2p - b = 1

=> b = 1

   p = 1

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