看板 Math 關於我們 聯絡資訊
※ 引述《QQLeopard (QQ)》之銘言: : 1. : https://i.imgur.com/YQvH1pA.jpg f(x) = ax^2 + bx = a(x + b/(2a))^2 - (b^2)/(4a) a =/= 0 f(x - 106)有最大值 = 1 => a < 0,4a + b^2 = 0 (4 + t + 2 - t)/2 = -b/2a => 6a + b = 0 => 4a + 36a^2 = 0 => a = -1/9,b = 2/3 => f(x) = -(1/9)x^2 + (2/3)x : 2. : https://i.imgur.com/Wr7MYOV.jpg y(x) = x^2 + kx + a > 2x + 1 for all k, x => x^2 + (k - 2)x + (a - 1) > 0 for all k, x => (k - 2)^2 - 4(a - 1) < 0 for all k => k^2 - 4k + 4(2 - a) < 0 for all k 應該不存在這種a滿足all k的情況 : 3. : https://i.imgur.com/sAD6Vic.jpg : 有請神人求解謝謝你們:) -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 111.243.58.177 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1507309577.A.3B9.html
QQLeopard : 謝謝你:) 10/07 01:33