作者wayne2011 (今年十三號星期五)
看板Math
標題Re: [中學] 三角函數
時間Thu Oct 19 10:38:16 2017
※ 引述《wayne2011 (今年十三號星期五)》之銘言:
: ※ 引述《Honor1984 (奈何上天造化弄人?)》之銘言:
: : sin(b)
: : ------------
: : sin(a)sin(r)
: : 2△CDE CA CD CB CE
: : = ------------------------------
: : 2△CAD 2△CBE CD CE
: : = (3/2) (11/6)
: : = 11/4
: 原式
: =cos(gamma+alpha)/[sin(gamma)*sin(alpha)]
: =cot(gamma)cot(alpha)-1 連比例
: 6/5=BCsin(gamma)/CAsin(alpha+beta)...分定 BE:DE:DA = 6:3:2
: 6/5=BCsin(gamma)/CAcos(gamma)...正餘弦互換 2 1
: cot(gamma)=5BC/6CA,同理,cot(alpha)=9CA/2BC. 3 2
: =(15/4)-1=11/4...ans
參考"標準奧數教程(初三分冊)"
習題2.1的4th題
2*6/(2+3)(3+6)=sin(gamma)sin(alpha)/cos(gamma)cos(alpha)
cot(gamma)cot(alpha)=15/4...此題為證明
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推 JI1 : how do you understand the origin? 10/19 10:41
推 JI1 : and how do you understand the number zero? 10/19 10:43
→ wayne2011 : i don't know~maybe still have a long time to go~ 10/19 10:43
推 JI1 : how do you understand the beginning...?:) 10/19 10:44