推 BlueArthur : 感謝大大!!!! 10/20 03:28
※ 引述《BlueArthur ( )》之銘言:
: 求人幫解,完全看不董啊 Orz....
: https://goo.gl/DEvfxM
: 有請大大們幫忙!!
dN/dt = rN(1 - N/k)
= -(r/k)N(N - k)
=> (1/k)[1/(N - k) - 1/N]dN = -(r/k)dt
=> ln[(N - k)/N] = -rt + C
=> 1 - k/N = Aexp(-rt)
=> N = k/[1 - Aexp(-rt)]
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