看板 Math 關於我們 聯絡資訊
※ 引述《gintgonhz (Determination)》之銘言: : 上來請教各位,請幫忙解這兩題,三角函數想融會貫通不知道有什麼祕方?XD : https://i.imgur.com/4LYwhve.jpg (1) k/3 = cotθtanθ = 1 => k = 3 (2) 11/3 = cotθ + tanθ = (secθ)^2 / tanθ = 1 / (sinθcosθ) => sinθcosθ = 3/11 : https://i.imgur.com/ihDePot.jpg (1/2) 30 π/180 - [π/4 - (1/2) 30 π/180 - (1/4)√3] = π/6 - π/4 + (1/4)√3 = (1/4)√3 - π/12 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 118.165.144.173 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1510673341.A.7D7.html
alan23273850: 符號好美~ 另外第二題我會先讓 cot=cos/sin、tan= 11/15 00:29
alan23273850: sin/cos,兩個分數再相加,通分會得到很好結果 11/15 00:29
Honor1984 : 對 11/15 22:39