看板 Math 關於我們 聯絡資訊
※ 引述《semmy214 (黃小六)》之銘言: : https://imgur.com/a/49H88 : 這方法我還不太熟~ : 請各位大大 指導~ (-5v + 2u)du + (-2u - 4v)dv = 0 v = ku dv = udk + kdu (-5k + 2)udu + (-2 - 4k)u[udk + kdu] = 0 => [(-5k + 2)u + (-2k - 4k^2)u]du + (-2 - 4k)u^2 dk = 0 => (1/u)du + [-2(1 + 2k)/(-4k^2 - 7k + 2)]dk = 0 => dln|u| - 2[-(4/3)/(-4k + 1) + (2/3)/(k + 2)]dk = 0 => ln|u| - (2/3)ln|k - 1/4| - (4/3)ln|k + 2| = c => ln|u| - (2/3)ln|v/u - 1/4| - (4/3)ln|v/u + 2| = c -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 111.243.53.182 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1516463887.A.19E.html