Re: [微積] 一題微積

[xavier13540 (柊 四千)]

Put x=0 in xJ''(x)+J'(x)+xJ(x)=0 to find

J'(0) = 0.

Note that for x≠0 we have

J''(x) = -J'(x)/x - J(x)
       = -(J'(x)-J'(0))/(x-0) - J(x).

Let x→0 to obtain

J''(0) = -J''(0) - J(0) = -J''(0) - 1,

that is,

J''(0) = -1/2. □

--
→ iWRZ:傳說原本小紅帽是R-18故事......
→ iWRZ:天方夜譚也是很多R-18
推 ID556:格林童話原也是 R-18
推 flysonics:Fate/SN也是R-18
推 belmontc:H-game也都是R-18
→ minoru04:油廠國小也是R-18
--
※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 140.112.229.87
※ 文章網址: https://www.ptt.cc/bbs/Math/M.1521499629.A.849.html
※ 編輯: xavier13540 (140.112.229.87), 03/20/2018 06:49:16