推 CBH : 酷! 08/03 17:55
※ 引述《CBH (吸逼A去)》之銘言:
: https://imgur.com/Ik8fnCQ
: 3Q
: 第2題少寫=0
1.
令 t = (103-x)^1/5 則 (x-21)^1/5 = (82-t^5)^1/5
原式為
t + (82-t^5)^1/5 = 2
=> 82-t^5 = (2-t)^5
=> t^4 - 4t^3 + 8t^2 - 8t - 5 = 0
=> (t^2-2t-1)(t^2-2t+5) = 0
=> 實根為 t = 1±√2
=> x = 62±29√2
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