看板 Math 關於我們 聯絡資訊
※ 引述《nini851216 (解壓縮)》之銘言: : https://i.imgur.com/nB6oRph.jpg : 字太醜見諒 : 再來就不會了.. : 請求大大幫忙 : https://i.imgur.com/BDv93Cp.jpg : 答案是這個 : https://i.imgur.com/L3KLflc.jpg yy" + (y')^2 = 2 => y"/y' + y'/y = 2/(yy') => [lny']' + [lny]' = 2/(yy') => [ln(yy')]' = 2/(yy') => yy' = 2x + C_1 => (1/2) (y^2)' = 2x + C_1 => (1/2)y^2 = x^2 + C_1x 寫成這樣就可以了 => y^2 = 2{[x + C_2]^2 - (C_2)^2} => x + C_2 = +-(1/2)sqrt(2y^2 + C_3) -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 61.56.10.112 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1534484837.A.2CB.html
nini851216 : 謝謝你 我會了! 08/17 14:11