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Suppose p is an integer with p >= 2 and the following property: for any two integers m,n if p|(mn) then either p|m or p|n (or both). Show that p must be prime. 目前的想法是利用反證法: Assume p is not a prime We can write p = ab, where a, b are integers and not equal to 1 So gcd(p,n)=a and gcd(p,m)=b Then a= px + ny and b = pq + mr ab = (xb)a + (yb)n = (qa)p + (ra)m 再來就卡住了 跪求大家幫忙 謝謝 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 130.126.255.60 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1537056679.A.122.html