看板 Python 關於我們 聯絡資訊
nameDict = {} for name in nameList: if name[0] not in nameDict: nameDict[name[0]] = 1 else: nameDict[name[0]] += 1 用dictionary來計算 字母當作key,出現次數當作value -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 114.36.28.48 ※ 文章網址: https://www.ptt.cc/bbs/Python/M.1426603038.A.F17.html
SoldierGame: nameDict[name[0]] = nameDict.get(name[0], 0) + 1 03/18 00:45
fischcheng: elegant solution! 03/18 04:29
alair99: 漂亮~~ 03/20 17:04