[問題] 吃藥隨機分配

[jackflu (jackflu)]

目的：不重複的分配吃藥，假設有7種藥，3餐吃2顆，睡前吃1顆。

想要達成：

Morning :  [4, 5]
Noon  :    [7, 3]
Night :    [2, 1]
Sleep :    [6]



我寫的 2.7版本

import random

drug = [1, 2, 3, 4, 5, 6, 7 ]

take = random.sample(drug,2)
print "Morning : " , take

take = random.sample(drug,2)
print "Noon : " , take

take = random.sample(drug,2)
print "Night : " , take

take = random.sample(drug,1)
print "Sleep : " , take

我只能寫出會重複的

新手爬文後想不出來請教

感謝指導

---更新 感謝幾位大大 目前只看的懂一樓大大的---

import random

drug = [1, 2, 3, 4, 5, 6, 7 ]

take = random.sample(drug,2)
print "Morning : " , take
for t in take : drug.remove(t)

take = random.sample(drug,2)
print "Noon : " , take
for t in take : drug.remove(t)

take = random.sample(drug,2)
print "Night : " , take
for t in take : drug.remove(t)

take = random.sample(drug,1)


有更漂亮的寫法嗎？



--- 再次感謝 換了看起來比較舒服 ---

import random
drug = [1, 2, 3, 4, 5, 6, 7 ]

random.shuffle(drug)

print drug
print "Moring: ",(drug[0],drug[1])
print "Noon: "  ,(drug[2],drug[3])
print "Night: " ,(drug[4],drug[5])
print "Sleep: " , drug[6]

還希望可以更簡短，繼續研究看看

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※ 文章網址: https://www.ptt.cc/bbs/Python/M.1498795285.A.BC8.html
→ kuso0516: for t in take : drug.remove(t)
推 CaptainH: permutation ...
→ CaptainH: or shuffle
→ y3k: 最快就是拿出來後要從drug中移除阿...
推 APM99: drug = [ s for s in drug if s not in take]
※ 編輯: jackflu (36.231.113.217), 06/30/2017 21:09:35
推 ErnieYang: 用shuffle 然後pop
→ y3k: random.shuffle(drug) 然後print(drug)出來看看便知
※ 編輯: jackflu (1.163.97.26), 07/01/2017 18:03:42
→ y3k: 我認為不需要了 再短會降低可閱姓