看板 Python 關於我們 聯絡資訊
目前寫了判斷母音的code如下 word = input() count = 0 a = e = i = o = u = 0 for num in word.lower(): if num in 'a': a = 1 elif num in 'e': e = 1 elif num in 'i': i = 1 elif num in 'o': o = 1 elif num in 'u': u = 1 count = a + e + i + o + u print(count) 自己覺得這code看起來很笨......想問是不是有更好的寫法, 另外也想問for num in word.lower()這行for的運作是怎麼樣呢? 知道word.lower()是變小寫的意思, 但num in word.lower()的意思看了很久還是不太能理解> < -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 140.112.25.99 ※ 文章網址: https://www.ptt.cc/bbs/Python/M.1509698343.A.F90.html ※ 編輯: tnzikom (140.112.25.99), 11/03/2017 17:09:11
Django: for num in word.lower(): if num in 'aeiou': count += 111/03 17:38
Django: (請自行排版) 另外你本來的寫法是錯的,aeiou的值沒有累加11/03 17:39
抱歉我打錯了!!!是要問有幾種母音
johnlinvc: import re11/03 17:47
johnlinvc: count=len(re.findall("[AEIOU]", word,re.I))11/03 17:48
※ 編輯: tnzikom (140.112.25.99), 11/03/2017 18:29:08
NTUGG: str.count(....) 11/03 18:35
Yshuan: [ch in word.lower() for ch in 'aeiou'].count(True) 11/03 21:22
Yshuan: num in word.lower() #小寫的word是否有num變數代表的字母 11/03 21:24
bibo9901: len( set("aeiou") & set(word) ) 11/03 22:44
goldflower: word='ptT is Back' for num in word作用如同 11/03 23:27
goldflower: for num in ['p','t','t',' ','i','s',' ',......] 11/03 23:28
lance8537: 感覺好leetcode 11/05 11:08