→ celestialgod: let alpha = 1-exp(-(y/b)^a) 10/14 01:02
→ celestialgod: 可以推出來 y = (-b^a*log(1-alpha))^(1/a) 10/14 01:02
→ celestialgod: 所以Q_Y(alpha) = (-b^a*log(1-alpha))^(1/a) 10/14 01:03
→ AmigoSafin: 謝謝～請問你第二步怎麼做出的呢？我會做到log(-y/b) 10/14 03:08
→ AmigoSafin: =log(1-alpha)/a, log(-y/b)=log(1-alpha)*e^(1/a) 10/14 03:09
→ celestialgod: 1. 1-alpha = exp(-(y/b)^a) 10/14 04:38
→ celestialgod: 2. 兩邊取log => log(1-alpha) = -y^a / b^a 10/14 04:39
→ celestialgod: 3. 兩邊乘上-b^a => b^a*log(1-alpha) = y^a 10/14 04:40
→ celestialgod: 最後兩邊開a次方根就可以得到跟上面一樣的結果了 10/14 04:40
→ AmigoSafin: 了解了 開a次方根就是*(1/a) 謝謝了！！ 10/15 11:00