推 EIORU: 1. C1R678/C6R67/C9R78 HAS 6, C234R678 NO 6 08/02 22:43
→ EIORU: 2. C1R4 C3R6 HAS 39, C3R4=5 08/02 22:44
推 funkie: 1. 考慮R1和R8的4, R1C3(4,6)=>R8C2(4,5,6)不能是6。因為 08/02 23:52
→ funkie: 會變成非唯一解 08/02 23:52
→ funkie: 2. R1C3(4,6),R8C2(4,5) and R9C3(5,6)=>R1C3=4 or R8C2= 08/03 00:03
→ funkie: 4 => R8C3 不是 4 08/03 00:03