→ yeebon: chx64的1/2悖論真的很經典呢07/22 16:41
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※ 文章網址: https://www.ptt.cc/bbs/Math/M.1511689236.A.851.html
※ 引述《nokol (騷人墨客)》之銘言:
: http://i.imgur.com/aAcHjwx.jpg
: Example 3
: 想請教站上大師指點
: 謝謝您,謝謝。
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: Sent from JPTT on my Samsung SM-G955F.
3xy' - y = lnx + 1 --> Cauchy-Euler form--> y = x^m
yh: x^m(3m-1) = 0 --> m = 1/3
y = Cyh + C'yp, guess yp = C'lnx
3x(Cx^1/3 + C'lnx)' - (Cx^1/3 + C'lnx) = lnx + 1
Cx^1/3 + 3C' - Cx^1/3 - C'lnx = lnx + 1 --> C' = -1
y = Cx^1/3 + -lnx + 4, y(1) = -2 --> C = 2
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Fw: [問卦] 電影:決勝21點的機率問題 https://goo.gl/2BpbB7 #1MfN3FgZ (joke)